3x-1=x^2x^2+5

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Solution for 3x-1=x^2x^2+5 equation: 



3x-1=x^2x^2+5

We move all terms to the left:

3x-1-(x^2x^2+5)=0

We get rid of parentheses

-x^2x^2+3x-5-1=0

We add all the numbers together, and all the variables

-x^2x^2+3x-6=0

We move all terms containing x to the left, all other terms to the right

-x^2x^2+3x=6

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